• May 27th 2012, 03:02 AM
fqqs
I have to calculate this integral $\int_{ \beta }^{}$ $|z|dz$

when $\beta = [-i,i]$

so

$\gamma (t)= -i + ti$, $t \in [0,2]$

$\int_{0}^{2} |-i+ti|idt = i \int_{0}^{2} \sqrt{(t-1)^2} dt = i \int_{0}^{2} |t-1| dt = i (\int_{1}^{2} (t-1) dt - \int_{0}^{1} (t-1) dt ) = ...$

correct?
• May 27th 2012, 03:39 AM
Prove It