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Math Help - Integral Help

  1. #1
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    Integral Help

    Thanks!!
    Attached Thumbnails Attached Thumbnails Integral Help-70.gif  
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  2. #2
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    This is really easy.

    Have you tried u=\tan x?
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  3. #3
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    Re:

    Yea I agree. I just worked some really hard ones, then they stuck in this easy one. Kind of like playing with indeterminate limits then all of a sudden coming across one that converges by just plugging in the numbers.

    Thanks,
    -qbkr21
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  4. #4
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    Quote Originally Posted by qbkr21 View Post
    Yea I agree. I just worked some really hard ones, then they stuck in this easy one. Kind of like playing with indeterminate limits then all of a sudden coming across one that converges by just plugging in the numbers.

    Thanks,
    -qbkr21
    Use u=tanx \rightarrow du=sec^2x\,dx

    <br />
\int tan^3x\,sec^2x\,dx = \int u^3\,du = \dfrac{1}{4}\,u^4\,+C = \dfrac{1}{4}\,tan^4x\,+C<br />
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