If y= cos^2[x]-sin^2[x] then y'= I know how to do it if the exponent is after the x, but how would this be done? The answer key says -2sin(2x). Thanks
Follow Math Help Forum on Facebook and Google+
Originally Posted by jst706 If y= cos^2[x]-sin^2[x] Note that $\displaystyle \cos^2x-\sin^2x=\cos2x,$ now take the derivative.
View Tag Cloud