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Math Help - the chain rule...derivatives

  1. #1
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    the chain rule...derivatives

    f(t) = 11e2t + e6

    how do i do this one...? please help
    Last edited by mathaction; October 2nd 2007 at 09:10 PM.
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  2. #2
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    Quote Originally Posted by mathaction View Post
    f(t) = 11e2t + e6

    how do i do this one...? please help
    If that is
    f(t) = 11e^(2t) +e^6,
    then,
    f'(t) = 11*e^(2t) *2 +0
    f'(t) = 22e^(2t) -------------------answer.

    If that is
    f(t) = (11e^2)t +e^6,
    then,
    f'(t) = (11e^2) +0
    f'(t) = 11e^2 ---------------------answer.

    Reminder, e^2 and e^6 are constants.
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