A) lim f(x) &

as x approches -2+

Since in the interval -2 <= x <= 1, or [-2,1], the f(x) is not defined, then as x approaches -2 from the right, it is stopped from moving beyond x=1, where f(x) = f(1) = sqrt(1+2) = sqrt(3).

Therefore the limit is sqrt(3).

B) Lim f(x)-

as x approaches -2

As x approaches -2 from the left, the limit of f(x) is the intersection of f(x) = x+3 and the vertical line x = -2

So,

f(x) = x+3, and when x = -2, f(x) = -2 +3 = 1.

Therefore, the limit is 1.