As h approaches 0, lim [cos((pi/2)+h) - cos(pi/2)] / h The answer is -1. Can someone please explain how to arrive at this answer? Are there special trig-based formulas I need to know to solve questions like this?
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Originally Posted by TWN As h approaches 0, lim [cos((pi/2)+h) - cos(pi/2)] / h The answer is -1. Can someone please explain how to arrive at this answer? Are there special trig-based formulas I need to know to solve questions like this? Two special limits you should know are and . In this case, we have (sum and difference identity)
Ah, I see. I was unaware of the sum and difference identities. Thank you! By the way, how do you write out the problems like that? It's so much easier to read than mine is!
Originally Posted by TWN Ah, I see. I was unaware of the sum and difference identities. Thank you! By the way, how do you write out the problems like that? It's so much easier to read than mine is! You can write in , just enclose your code between [tex] and [/tex] tags. For help with LaTeX, visit the LaTeX forum. There's a tutorial there.
Originally Posted by TWN As h approaches 0, lim [cos((pi/2)+h) - cos(pi/2)] / h The answer is -1. Can someone please explain how to arrive at this answer? Are there special trig-based formulas I need to know to solve questions like this? note the format of the limit ... ... this is the definition of in this case, and the limit is
That makes sense! Thank you both!
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