# Indefinite Integral

• May 14th 2012, 08:18 AM
Bashyboy
Indefinite Integral
I attached a file containing the problem; I circled the answer, but it is not the correct answer. What did I do wrong?
• May 14th 2012, 08:46 AM
skeeter
Re: Indefinite Integral
$\int \frac{2x}{(x-1)^2} \, dx$

$u = x-1$

$x = u+1$

$du = dx$

$\int \frac{2(u+1)}{u^2} \, du = 2 \int \frac{1}{u} + \frac{1}{u^2} \, du$

integrate and back-substitute