I attached a file containing the problem; I circled the answer, but it is not the correct answer. What did I do wrong?

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- May 14th 2012, 07:18 AMBashyboyIndefinite Integral
I attached a file containing the problem; I circled the answer, but it is not the correct answer. What did I do wrong?

- May 14th 2012, 07:46 AMskeeterRe: Indefinite Integral
$\displaystyle \int \frac{2x}{(x-1)^2} \, dx$

$\displaystyle u = x-1$

$\displaystyle x = u+1$

$\displaystyle du = dx$

$\displaystyle \int \frac{2(u+1)}{u^2} \, du = 2 \int \frac{1}{u} + \frac{1}{u^2} \, du$

integrate and back-substitute