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Math Help - Find the equation of the tangent plane to the surface (vector calculus)

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    Find the equation of the tangent plane to the surface (vector calculus)

    Find the equation of the tangent plane to the surface z=x(x^2+y)^1/2 at the point (2,5,6)

    thank you
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    Re: Find the equation of the tangent plane to the surface (vector calculus)

    That's a pretty straight forward problem, isn't it? The gradient of f(x, y, z) where [tex]f(x, y, z)= x(x^2+ y^2)^{1/2}- z[tex] is a vector perpendicular to the surface. And once you have vector <A, B, C> perpendicular to the surface at (x_0, y_0, z_0), the tangent plane is given by A(x- x_0)+ B(y- y_0)+ C(z- z_0)= 0. Have you calculated that?
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