Actually is it as simple as G(x) = F((sinx)^2)??
I have an exam tomorrow and am trying to do past exam questions.Panicking!
The question tells us G(x)=integral between -1 and (sinx)^2 of e^t.tant dt. F(x)=integral between-1 and x of e^t.tant dt.
Write G(x) in terms of F(x). Find G'(x).
I think I have G'(x) as 2sinxcosx(e^(sinx)^2).tan((sinx)^2).
However, I'm not so sure of how to express G(x) in terms of F(X).
Can anyone help?