Hello, I am trying to understand the steps involved in integrating the following: 2e^2 + 6cosx Can someone please show me the steps. Thanks kindly if possible.
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WA , click "show steps"
$\displaystyle \begin{aligned} \int 2e^2 + 6 \cos x \ dx &= \int 2e^2 dx + \int 6 \cos x \ dx \\ &= 2e^2 \int dx + 6 \int \cos x \ dx \\&=2e^2 x + 6 \sin x +C\end{aligned}$
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