Thread: Evaluate the integral using trig substitution

1. Evaluate the integral using trig substitution

The integral from 0 to 1/2 of ((ln(2x+1))/(4x^2 +1))dx

2. Re: Evaluate the integral using trig substitution

$2x=tan \theta$

$2dx=\frac {d \theta}{cos^2 \theta}=\frac{cos^2 \theta + sin^2 \theta}{cos^2 \theta}d \theta= (1+tan^2 \theta)d \theta$