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Thread: Evaluate the integral using trig substitution

  1. May 6th 2012, 01:30 PM #1
    sharp
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    Evaluate the integral using trig substitution

    The integral from 0 to 1/2 of ((ln(2x+1))/(4x^2 +1))dx
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  2. May 7th 2012, 10:09 PM #2
    Kiwi_Dave
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    Re: Evaluate the integral using trig substitution

    2x=tan \theta

    2dx=\frac {d \theta}{cos^2 \theta}=\frac{cos^2 \theta + sin^2 \theta}{cos^2 \theta}d \theta= (1+tan^2 \theta)d \theta
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