Results 1 to 7 of 7

Math Help - need a bit of help with derivatives...thanks

  1. #1
    Banned
    Joined
    Oct 2007
    Posts
    45

    need a bit of help with derivatives...thanks



    need some help with this one...
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by mathaction View Post


    need some help with this one...
    use the product rule: \frac d{dx} f(x)g(x) = f'(x)g(x) + g'(x)f(x)

    here: f(x) = t^2 + 4 and g(x) = e^t
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Banned
    Joined
    Oct 2007
    Posts
    45
    Quote Originally Posted by Jhevon View Post
    use the product rule: \frac d{dx} f(x)g(x) = f'(x)g(x) + g'(x)f(x)

    here: f(x) = t^2 + 4 and g(x) = e^t

    ok...i came up with this...

    e^t*3t^2+e^t*t^3+4
    Follow Math Help Forum on Facebook and Google+

  4. #4
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by mathaction View Post
    ok...i came up with this...

    e^t*3t^2+e^t*t^3+4
    that's incorrect. try one more time. and use parentheses
    Follow Math Help Forum on Facebook and Google+

  5. #5
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by mathaction View Post


    need some help with this one...
    z'(t) = 3t^2e^t + \left( t^3 + 4 \right)e^t = \left( t^3 + 3t^2 + 4 \right)e^t
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Banned
    Joined
    Oct 2007
    Posts
    45
    oh ok...so its like just combining like terms...
    Follow Math Help Forum on Facebook and Google+

  7. #7
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by mathaction View Post
    oh ok...so its like just combining like terms...
    yes, at the end, after i took derivatives
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Derivatives and Anti-Derivatives
    Posted in the Calculus Forum
    Replies: 7
    Last Post: February 6th 2011, 06:21 AM
  2. Replies: 1
    Last Post: July 19th 2010, 04:09 PM
  3. Derivatives with both a and y
    Posted in the Calculus Forum
    Replies: 3
    Last Post: October 4th 2009, 09:17 AM
  4. Replies: 4
    Last Post: February 10th 2009, 09:54 PM
  5. Trig derivatives/anti-derivatives
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 10th 2009, 01:34 PM

Search Tags


/mathhelpforum @mathhelpforum