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Math Help - evaluate the integral

  1. #1
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    evaluate the integral

    evaluate the integral from 0 to 1/2 of (ln(2x+1))/(4x2+1)dx. any help is greatly appreciated, thank you in advance
    Last edited by tannergilligan; May 4th 2012 at 01:53 PM.
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  2. #2
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    Re: evaluate the integral

    Did you mean \int_0^{1/2}\ln \frac{2x+1}{4x^2+1}dx?

    If so, remember log(a/b)=log a - log b.

    You can then use integration by parts on ln (4x^2+1).
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  3. #3
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    Re: evaluate the integral

    no, I edited it appropriately as to eliminate any confusion. btw, how do you create an integral within the text?
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    Re: evaluate the integral

    Quote Originally Posted by tannergilligan View Post
    no, I edited it appropriately as to eliminate any confusion.
    In that case, take a look at integrate log(2x+1)/(4x^2+1) dx - Wolfram|Alpha .


    Quote Originally Posted by tannergilligan View Post
    btw, how do you create an integral within the text?
    LaTeX Help
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  5. #5
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    Re: evaluate the integral

    I have already used the integral calculator on wolfram, but that really isn't a solution. I know in this thread: <http://mathhelpforum.com/calculus/42341-integrate-ln-tanx-1-a.html> , he says on the 3rd to last line that someone had already solved this integral earlier, but I have no idea where this solution is. any help is greatly appreciated.
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  6. #6
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    Re: evaluate the integral

    If it makes any difference to you guys, it can also be written as (1/2)[integral from 0 to 1 (ln(u+1))/(u^2+1)du] using the substitution u=2x. not a big difference, but enough to make it simpler to look at.
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