y= tan^(-1)[x^2-1]^(1/2) + csc^(-1)x

i cannot get to the answer, please help.

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- Oct 1st 2007, 08:01 PMmstsoyderivative of inverse trig function
y= tan^(-1)[x^2-1]^(1/2) + csc^(-1)x

i cannot get to the answer, please help. - Oct 1st 2007, 08:15 PMJhevon
- Oct 1st 2007, 08:21 PMmstsoy
no i have definitely tried working it out already.

i took derivative of both sides of the plus sign

the answer should come out to zero

but im not getting newhere near that.

im getting something like x/ [(x^2 -1)(x^2 -1)^2] - 1/[|x|(x^2-1)^2]

before simplifying, and after simplifying its not zero..urgh i cannot get it