The problem is a definite integral from 0 to infinity for the function f(x) = 38/(z^2 + 40z + 39).

The problem here is that I don't know how to solve the integral. I can break the denominator into (z+39)(z+1) but I don't know where to go from here.

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- May 1st 2012, 06:21 PMTenaciousEImproper Integral
The problem is a definite integral from 0 to infinity for the function f(x) = 38/(z^2 + 40z + 39).

The problem here is that I don't know how to solve the integral. I can break the denominator into (z+39)(z+1) but I don't know where to go from here. - May 1st 2012, 06:32 PMskeeterRe: Improper Integral