The problem is $\displaystyle \int_1^e\frac{(\1+lnx)^2}{x}dx$

So, I figured that $\displaystyle u\equiv\1+lnx$,

then $\displaystyle \frac{du}{dx} = \frac{1}{x}\rightarrow{dx} = {x}{du}$

coming upon this step I am not entirely confident with what I am suppose to be substituting.