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Thread: Fifth degree equation

  1. April 26th 2012, 11:13 PM #1
    Mhmh96
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    Fifth degree equation

    How to use newton-rhapson to solve like these equation ?

    (1) x^5+15x+12=0
    (2)x^5+330x-4170=0
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  2. April 26th 2012, 11:23 PM #2
    Prove It
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    Re: Fifth degree equation

    Choose a suitable starting value \displaystyle \begin{align*} x_0 \end{align*}, then

    \displaystyle \begin{align*} x_{n + 1} = x_n - \frac{f(x_n)}{f'(x_n)} \end{align*}
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  3. April 26th 2012, 11:38 PM #3
    biffboy
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    Re: Fifth degree equation

    For no.1 Expression is negative when x=-1 and positive when x=0 so choose a starting value between -1 and 0
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