# Fifth degree equation

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• April 27th 2012, 12:13 AM
Mhmh96
Fifth degree equation
How to use newton-rhapson to solve like these equation ?

(1) x^5+15x+12=0
(2)x^5+330x-4170=0
• April 27th 2012, 12:23 AM
Prove It
Re: Fifth degree equation
Choose a suitable starting value \displaystyle \begin{align*} x_0 \end{align*}, then

\displaystyle \begin{align*} x_{n + 1} = x_n - \frac{f(x_n)}{f'(x_n)} \end{align*}
• April 27th 2012, 12:38 AM
biffboy
Re: Fifth degree equation
For no.1 Expression is negative when x=-1 and positive when x=0 so choose a starting value between -1 and 0