Let A = {z|z^{6}= '3 + i} and B = {z|Im(z) > 0} and C = {z|Re(z) > 0

(where '3 means the square root of 3)

.. I found the z^{6}to be: (using k = 0,1,2,3,4,5 in that order)

z_{1}= z^{1/6}(cos pi/6 + isin pi/6)

z_{2}= z^{1/6}(cos 2/pi + isin 2/pi)

z_{3}= z^{1/6}(cos 5pi/6 + isin 5pi/6)

z_{4}= z^{1/6}(cos 7pi/6 + ison 7pi/6)

z_{5}= z^{1/6}(cos 9pi/6 + isin 9pi/6)

z_{6}=z^{1/6}(cos 11pi/6 + isin 11pi/6)

I've been asked to find the 'intersecting' of sets A, B, and C.. But not really sure how I'm meant to compapre real, imaginary and complex numbers together..