How can I solve that without using L'Hôpital's rule (which is considered illegal in my calculus class)? :D

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- February 22nd 2006, 05:57 PMcinderlimit question

How can I solve that without using L'Hôpital's rule (which is considered illegal in my calculus class)? :D - February 23rd 2006, 10:57 AMTD!
For small x (which we have here, since we're letting x tend to 0) you can use the first order Taylor expansion for sin(x) which is x. So for small x:

It's also possible that you have to use the 'standard limit':

In that case, rewrite as follows:

- February 23rd 2006, 12:43 PMThePerfectHacker
Cinder I realize that this is off topic. I looked at your LaTex code an saw that you wrote that limit in array mode. I think it is easier if you write it as:

\lim_{n\to 0}\frac{\sin 2x}{\sin 3x}