Derivative Of A Natural Logarithm

I am given the function f(x) = ln(lnx^2) to differentiate; but I am not entirely certain how to do this. Could someone possibly help me?

Thank you

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Originally Posted by Bashyboy

I am given the function f(x) = ln(lnx^2) to differentiate; but I am not entirely certain how to do this. Could someone possibly help me?

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Note that so

You need to know this: the derivative of f(x)= ln(u(x)) is [tex]\frac{1}{u}\frac{du}{dx}[/itex].

As Plato said, . "ln(2)" is a constant and its derivative is 0.

so you have ln(u(x)) with u(x)= ln(x).