Results 1 to 5 of 5

Math Help - tangent line help plz

  1. #1
    Newbie
    Joined
    Mar 2012
    From
    China
    Posts
    17

    tangent line help plz

    hi everyone

    find equation of tangent line to curve y = 3x^2 + e^(1-x) when x =1

    please show working so i can follow along thankyou!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member
    Joined
    Nov 2011
    From
    Crna Gora
    Posts
    420
    Thanks
    64

    Re: tangent line help plz

    Quote Originally Posted by tankertert View Post
    hi everyone

    find equation of tangent line to curve y = 3x^2 + e^(1-x) when x =1

    please show working so i can follow along thankyou!
    f'(x)=6x-e^{1-x} , see WA

    Equation of tangent to curve at point a is given by :

    y=f(a)+f'(a)(x-a)
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2012
    From
    China
    Posts
    17

    Re: tangent line help plz

    so i should be subbing it in to get

    y = (3 x 1^2 + e^{1-1}) + (6 x 1 - e^{1-1})(x-1)

    and then solving for x?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member
    Joined
    Nov 2011
    From
    Crna Gora
    Posts
    420
    Thanks
    64

    Re: tangent line help plz

    simplify expression...
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Mar 2012
    From
    China
    Posts
    17

    Re: tangent line help plz

    sorry thats i meant

    so answer is

    y = 3x +(x-1)(6x-1) +1 ?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: November 4th 2011, 07:42 PM
  2. Replies: 6
    Last Post: January 12th 2011, 03:38 PM
  3. Replies: 5
    Last Post: November 4th 2009, 07:49 PM
  4. tangent line & normal line question
    Posted in the Calculus Forum
    Replies: 4
    Last Post: March 15th 2009, 04:45 AM
  5. Replies: 4
    Last Post: March 17th 2008, 02:53 PM

Search Tags


/mathhelpforum @mathhelpforum