1. ## [SOLVED] area question

2. Originally Posted by jst706
yes you did. how did you end up with $\displaystyle x(2 - x)$?

you want $\displaystyle \int_{0}^{2} x \sqrt {4 - x^2}~dx$

use the substitution $\displaystyle u = 4 - x^2$

3. Thanks for the help. I actually tried it my wrong way, then substitution, then my wrong way again and got the wrong answer every time, but I just redid it with substitution and got the right answer...thanks a lot for the help.