I'm having a bit of difficulty with this one. Can anyone help?

Many thanks.

Q.log_{e}x dx

Attempt:u = log_{e}x => du = dx

dv = => dv = x^{-2}=> v = x^{-2}=>

u dv = uv - v du => log_{e}x dx => log_{e}x + => + => -

log_{e}x dx = => => =>(From text book): (1 - ln2)

Ans.: