how do you find dy/dx for: x^2 - 3lny+y^2=10
Use implicit diffrenciation,Originally Posted by sheven
$\displaystyle 2x-\frac{3}{y}\frac{dy}{dx}+2y\frac{dy}{dx}=0$
Thus,
$\displaystyle \frac{dy}{dx}\left(2y-\frac{3}{y}\right)=-2x$
Thus,
$\displaystyle \frac{dy}{dx}=\frac{2x}{\frac{3}{y}-2y}$Thus,
$\displaystyle \frac{dy}{dx}=\frac{2xy}{3-2y^2}$