how do you find dy/dx for: x^2 - 3lny+y^2=10

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- Feb 22nd 2006, 04:12 PMshevendifferentiate
how do you find dy/dx for: x^2 - 3lny+y^2=10

- Feb 22nd 2006, 06:12 PMVigo
Sheven, it is in our book I will show you tomorrow. p. 322 #73

The answer is in the back since it is odd.

I have several of the other answers. They are all somewhere in the book so if Frankenstein's otebook is there we can look them up. - Feb 23rd 2006, 12:27 PMThePerfectHackerQuote:

Originally Posted by**sheven**

$\displaystyle 2x-\frac{3}{y}\frac{dy}{dx}+2y\frac{dy}{dx}=0$

Thus,

$\displaystyle \frac{dy}{dx}\left(2y-\frac{3}{y}\right)=-2x$

Thus,

$\displaystyle \frac{dy}{dx}=\frac{2x}{\frac{3}{y}-2y}$Thus,

$\displaystyle \frac{dy}{dx}=\frac{2xy}{3-2y^2}$