Thread: completely expand the ln function, then find the derivative

Expression= lnx-ln(e^xlnx)=lnx-(lne^x+ln(lnx)=lnx-x-ln(lnx)

Derivative=1/x-1-1/(xlnx) (The last term came from 1/lnx times 1/x by the chain rule)

Originally Posted by rabert1

Are you saying that you do not know the "laws of logarithms"? It seems strange that you would be taking a course that asked you find derivatives of logarithm functions if you have never taken a course that dealt with logarithms.