Hi guys.

equation of tangent line to the curve $\displaystyle y = 3x^2 + e^{1-x}$ when x=1

i tried and got 0

can you show me how to solve with working please.

thank you!

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- Apr 17th 2012, 12:00 AMtankerterttangent line curve
Hi guys.

equation of tangent line to the curve $\displaystyle y = 3x^2 + e^{1-x}$ when x=1

i tried and got 0

can you show me how to solve with working please.

thank you! - Apr 17th 2012, 12:29 AMbiffboyRe: tangent line curve
dy/dx=6x-1 So when x=1 gradient of tangent=5 Also when x=1 y=2+e

So you want a straight line with gradient 5 through the point (1,2+e) - Apr 17th 2012, 12:42 AMa tutorRe: tangent line curve
- Apr 17th 2012, 02:02 AMtankertertRe: tangent line curve
- Apr 17th 2012, 02:32 AMbiffboyRe: tangent line curve
So now dy/dx=6x-e^1-x When x=1 y=4 and dy/dx=5 Require straight line through (1,4) with gradient 5

- Apr 17th 2012, 08:47 PMtankertertRe: tangent line curve