Hello everyone

I am studying tangents and come across this kind of problem where I am going to find the equation for one or more tangent with a specific directioncoefficient for an function.

Example:

Find the tangents for the funtion $\displaystyle y = 3x^2 - 2x + 1$ that has an directioncoefficient of 4.

How do I solve this kind of problem? I am halfway through, I think.

First we get the derivate for the function, which is:

$\displaystyle y = 6x - 2$

The we check and see for what X value Y equals 4, correct?

$\displaystyle 4 = 6x - 2$

$\displaystyle 1 = x $

And after that? Assuming that the above is correct.