Let $\displaystyle f(t)=3-|t-3|$ on the interval $\displaystyle [-1,5]$. Find the absolute maximum and absolute minimum of $\displaystyle f(t)$ on this interval.

The absolute max occurs at $\displaystyle t = 3$

The absolute min occurs at$\displaystyle t = -1$

I think I am doing this wrong. Those are the correct answers but I have no idea how 3 is the max. fuggled to me.