# Solving the system of two equations in two unknowns

• Apr 12th 2012, 04:45 PM
Lexy
Solving the system of two equations in two unknowns
I'm going through these tutorials for Calc III, and I came upon this slide:

Attachment 23584

source:MATH 311 - Calculus III Resources

How did the author solve for s and t?
• Apr 12th 2012, 05:55 PM
skeeter
Re: Solving the system of two equations in two unknowns
Quote:

Originally Posted by Lexy
I'm going through these tutorials for Calc III, and I came upon this slide:

Attachment 23584

source:MATH 311 - Calculus III Resources

How did the author solve for s and t?

first equation ...

1 + t = 2s , solve for t

t = 2s - 1

substitute (2s - 1) for t in the second equation ... solve for s, then determine the value of t
• Apr 13th 2012, 08:26 AM
HallsofIvy
Re: Solving the system of two equations in two unknowns
That's one good method. Another is this: the two equations are 1+ t= 2s and -2+ 3t= 3+s. Multiply the first equation by 3 to get 3+ 3t= 6s. Now subtract the second equation from that: (3+ 3t)- (-2+ 3t)= 6s- (3+ s). The "t" terms cancel giving 5= 5s- 3. Solve that for s then put that value into either of the original equations to get an equation to solve for t.