# graph question

• September 29th 2007, 04:16 PM
jst706
graph question
http://i231.photobucket.com/albums/e...omage13/40.jpg
Can someone give me some help with this? It would be appreciated. Thanks
• September 29th 2007, 04:19 PM
Jhevon
Quote:

Originally Posted by jst706
http://i231.photobucket.com/albums/e...omage13/40.jpg
Can someone give me some help with this? It would be appreciated. Thanks

the length of the base of the rectangle is $(2 - x)$. The height is $x^2$. Area is length times width, thus the area of this rectangle is:

$A = (2 - x)x^2$

now, maximize that function