I think it is y'= (1)/(x)(In(In(Inx))) but I'm not sure.
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no. From the chain rule, you should get,
Originally Posted by tenner I think it is y'= (1)/(x)(In(In(Inx))) but I'm not sure. First of all, the function is not "In", it's "ln", which stands for "natural logarithm". Anyway Let Let Let Then
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