$\displaystyle \int\frac{arcsinx}{\sqrt(1-x^2)}dx $ pls do help on this problem, thanks
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Originally Posted by lawochekel $\displaystyle \int\frac{arcsinx}{\sqrt(1-x^2)}dx $ pls do help on this problem, thanks You should know that $\displaystyle \displaystyle \begin{align*} \frac{d}{dx}\left(\arcsin{x}\right) = \frac{1}{\sqrt{1 - x^2}} \end{align*}$, so there is a really obvious substitution to be made...
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