Thread: Another Calculus Problem.

e
∫ (x^2-1)/(x) dx=
1


A) e- (1/e)

B) e^2 - e

C) (e^2/2)-e+ (1/2)

D) e^2-2

E) (e^2/2)-(3/2)

Originally Posted by frozenflames

e
∫ (x^2-1)/(x) dx=
1


A) e- (1/e)

B) e^2 - e

C) (e^2/2)-e+ (1/2)

D) e^2-2

E) (e^2/2)-(3/2)

First find the antiderivative of

Which is,

Which is,
,
But it is taken from
Which by the fundamental theorem is,