if $\displaystyle x=z^2 \arctan(\frac{y}{z}) find \frac{d^2x}{dzdy} $ have attempted the problem above and here is what i got; $\displaystyle \frac{3z^4+9z^2y^2}{(z^2+y^2)^2} $ pls see to this solution if am in order, thanks.
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Shouldn't it be : $\displaystyle {\frac {{z}^{2} \left( {z}^{2}+3\,{y}^{2} \right) }{ \left( {z}^{2}+{y}^{2} \right) ^{2}}}$
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