where
so ... multiply your result by 9.8
Hi, I know
the gist of how to do these problems but I am getting the wrong answers.
A tank in the shape of an inverted right circular cone has height 6 meters and radius 3 meters. It is filled with 5 meters of hot chocolate. Find the work required to empty the tank by pumping the hot chocolate over the top of the tank. The density of hot chocolate is
volume= pi r^2
r=3, y=6 so r=.5y
distance is from 0 to 5 meters
density is given as 1010
So W= density * volume * distance
W= 1010 [pi(.5y)^2]dy(6-y)
w=intregal from 0 to 5 (6-y)1010pi(1/4)y^2dy
=(1010pi/4) intregal from 0 to 5, 6y^3-y^3dy
and so on... I got 74367.388 J but it's wrong. any help will be appreciated. Thanks
Thank you!
Also I have a really quick question, if instead of giving you density of a liquid, it give you the weight. Example. the weight of the liquid is 60 lbs/ft^3
What does that mean? I know F=ma=Density * Volume*acceleration so does that weight of a liquid= density*volume? Thanks