# Math Help - product rule and differentiate natural log function

1. ## product rule and differentiate natural log function

$g(x)= 3^x * ln(x)$

$g'(x)= (3^x)' (ln(x)) + (3^x) (ln(x))'$

$g'(x)= (3^xln3)(ln(x)) + (3^x)(\frac{1}{x})$

$g'(x)= (3^xln3)(ln(x)) + \frac{3^x}{x}$ \\can be simplified or stop here?

2. ## Re: product rule and differentiate natural log function

Originally Posted by rabert1
$g(x)= 3^x * ln(x)$

$g'(x)= (3^x)' (ln(x)) + (3^x) (ln(x))'$

$g'(x)= (3^xln3)(ln(x)) + (3^x)(\frac{1}{x})$

$g'(x)= (3^xln3)(ln(x)) + \frac{3^x}{x}$ \\can be simplified or stop here?
No. Just stop. But to be strictly correct it should be $\ln(3)$. It is a function.

3. ## Re: product rule and differentiate natural log function

Alternative form :

$g'(x)=3^x \cdot \ln x^{\ln 3}+3^x \cdot \ln e^{\frac{1}{x}}=3^x \cdot \ln \left(x^{\ln 3} \cdot e^{\frac{1}{x}}\right)$