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- Sep 29th 2007, 12:46 AM #1

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## If y= log {x + (1 + x^2)^1/2} what is dy/dx?

I hope someone can help me with this problem:

If y= log {x + (1 + x^2)^1/2} what is dy/dx?

apprantly the answer is dy/dx = (1 + x^2)^-1/2 , but I cannot see how to do it. Is it a function of a function? My lecturer showed us this on the board - but I still can't understand - so I would appreciate it if someone could help - thank you.

- Sep 29th 2007, 01:14 AM #2

- Sep 29th 2007, 05:39 AM #3

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- Sep 29th 2007, 06:06 AM #4

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- Sep 29th 2007, 07:14 AM #5