How do you integrate integrate integral(3t-2 / (t+1)) step by step? I understand that a three can be pulled out of the integral but not why.
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Originally Posted by Broseidon420 How do you integrate integrate integral(3t-2 / (t+1)) step by step? I understand that a three can be pulled out of the integral but not why. WA , click "show steps" $\displaystyle \int C\cdot f(x) \,dx=C \cdot \int f(x) \,dx$ , where C is some constant value .
Do you mean $\displaystyle \int \frac{3t-2}{t+1}dt$ or $\displaystyle \int 3t-\frac{2}{t+1}dt$? In the first case I'd write it as $\displaystyle \int \frac{3t+3-5}{t+1}dt$.
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