# Thread: Integration Problem

1. ## Integration Problem

How do you integrate integrate integral(3t-2 / (t+1)) step by step? I understand that a three can be pulled out of the integral but not why.

2. ## Re: Integration Problem

Originally Posted by Broseidon420
How do you integrate integrate integral(3t-2 / (t+1)) step by step? I understand that a three can be pulled out of the integral but not why.
WA , click "show steps"

$\int C\cdot f(x) \,dx=C \cdot \int f(x) \,dx$ , where C is some constant value .

3. ## Re: Integration Problem

Do you mean $\int \frac{3t-2}{t+1}dt$ or $\int 3t-\frac{2}{t+1}dt$?

In the first case I'd write it as $\int \frac{3t+3-5}{t+1}dt$.