Find the area of a triangle enclosed by axes and tangent to y = 1/x

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- April 2nd 2012, 02:09 PMjoshuaaFind the area of a triangle.
Find the area of a triangle enclosed by axes and tangent to y = 1/x

(Crying) - April 2nd 2012, 02:13 PMMathVideosRe: Find the area of a triangle.
Where do you run into your problem? Finding the tangent line? Also, there's an infinite amount of triangles that could be made. Do they specify anything else?

- April 2nd 2012, 02:35 PMjoshuaaRe: Find the area of a triangle.
Could this picture help you?

Attachment 23501 - April 2nd 2012, 06:10 PMProve ItRe: Find the area of a triangle.
Well, let's see. If the function is , the derivative is . This tells us the gradient of the tangent line at any point x.

So the tangent line is of the form .

c is the y intercept. To find the x intercept, we'll let y = 0, and we find that

.

So the height of the triangle is c, the length is , which means the area is

So the area is - April 2nd 2012, 11:01 PMbiffboyRe: Find the area of a triangle.
Don't think that is correct. Example consider tangent at (1,1) Gradient is -1 Equation of tangent is y=-x+2 Intercepts are both 2 Area of triangle is 2

In general consider tangent at (k,m) Gradient of tangent is -1/k^2 Get the equation of the tangent and the intercepts. Knowing also that km=1 wil get area of triangle=2 - April 2nd 2012, 11:16 PMalexmahoneRe: Find the area of a triangle.
- April 3rd 2012, 02:11 AMjoshuaaRe: Find the area of a triangle.
Thank you very much. That was helpful :)