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Math Help - limit problem

  1. #1
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    limit problem

    I have no idea how to solve this..can somebody give me some help? thanks
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  2. #2
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    \cos \left( {\frac{\pi }{2} + h} \right) =  - \sin (h)
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  3. #3
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    Quote Originally Posted by jst706 View Post
    I have no idea how to solve this..can somebody give me some help? thanks
    Expand \cos(\pi/2+h) using the multiple angle formula:

    <br />
\frac{\cos(\pi/2+h)-\cos(\pi/2)}{h}=\frac{\cos(\pi/2)\cos(h)-\sin(\pi/2)\sin(h)-\cos(\pi/2)}{h}<br />

    ........... =\frac{\cos(\pi/2)(\cos(h)-1)-\sin(\pi/2)\sin(h)}{h}<br />

    ........... =\frac{\cos(\pi/2)(\cos(h)-1)}{h}-\frac{\sin(\pi/2)\sin(h)}{h}<br />

    The limit of the first term above is 0, and the second is -\sin(\pi/2)

    RonL
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