Hello everyone,

I am checking with an online calculator some derivatives and integrals but there is a specific result I don't understand.

In particular, for the derivative of arccos(x) I get this result:

$\displaystyle \frac{\mathrm{d} (arccos(x))}{\mathrm{d} x} = -1/ \sqrt{1-x^2}$

which is fine.

However when I ask what is the integral of derivative of arccos I get in particualar:

$\displaystyle \int -1/\sqrt{1-x^2}dx = -sin^{-1}(x)$

I was sure that the calculator would give arccos(x) as an answer, but it didn't. I suspect that there is no function whose indefinite integral equals arccos(x), and I should bound the integral but I am not so sure about it.

The answer to this could be long and I don't want to bother anyone, so any reference keywords for me to search in google would be also fine.

Also this question might be incomplete or not clear, so I am here to provide any other information if needed.