Given the sequence $\displaystyle a_n = \frac{7n^2 + 2}{5n^2 - 3},$

1a) Prove $\displaystyle a_n$ converges and then find the lim a.

b) If $\displaystyle \epsilon = \frac{1}{100}$, give a value of $\displaystyle N$ that will guarantee that $\displaystyle a_n \in V_{\epsilon}(a)$ whenever $\displaystyle n \ge N$. Then, verify this answer by picking an $\displaystyle n \ge N$ and checking $\displaystyle |a_n - a| < \epsilon$

Hmm, okay so obviously the limit is $\displaystyle \frac{7}{5}$.. but I know this from basic calculus (since we have the same power in the numerator/denominator). So would I proceed knowing this fact, and then proceeding with the convergence proof with $\displaystyle \epsilon$.. that is:

Let $\displaystyle \epsilon > 0$ be arbitrary. Then ____ ***have to findis a real number so there exists a natural number $\displaystyle N \in \mathbb{N}$ such that N > _____ ***same thing, have to findby the Archimedean Property. For this $\displaystyle N$ we have $\displaystyle |\frac{7n^2 + 2}{5n^2 - 3} - \frac{7}{5}| \le ... < ... < \epsilon$

OR, would I proceed to showing this converges by using the Monotone Convergence Thm (and thus pretty much making no assumptings as to what it converges to), and showing its bounded and monotone and therefore converges.

For part b, not sure how to do this.

EDIT: Err, wait, it isn't monotone everywhere.

Meh.