Find the derivative of the function below. f(x) = 16e^x + 3^x ... need some help on doing this problem...kinda in a hurry, thanks
Last edited by mer1988; Sep 27th 2007 at 10:22 PM. Reason: cuz im cool
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Originally Posted by mer1988 Find the derivative of the function below. f(x) = 16e^x + 3^x ... need some help on doing this problem...kinda in a hurry, thanks $\displaystyle \frac d{dx}a^x = a^x \ln a$, for $\displaystyle a>0$ a constant this rule works for $\displaystyle e^x$ as well, but generally, you just memorize that $\displaystyle \frac d{dx}e^x = e^x$
Originally Posted by Jhevon $\displaystyle \frac d{dx}a^x = a^x \ln a$, for $\displaystyle a>0$ a constant this rule works for $\displaystyle e^x$ as well, but generally, you just memorize that $\displaystyle \frac d{dx}e^x = e^x$ so then would the answer be, f`(x)= 16e^x+(ln3)3^x...?
Originally Posted by mer1988 so then would the answer be, f`(x)= 16e^x+(ln3)3^x...? yes
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