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Math Help - integration problem. Please Help

  1. #1
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    integration problem. Please Help

    cosh( k a sinθ) sin( k a cosθ) cosθ dθ = πka (how to prove that step by step)???????

    where π = pi
    = integration from zero to 2​π

    the book i am reading got mentioned that ; on expanding the cosh and cosine terms, four separate integrals may be obtained. from symmetry it may be shown that three of these integrals are identically zero leaving...
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  2. #2
    Super Member girdav's Avatar
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    Re: integration problem. Please Help

    Did you follow the hint? What did it give you?
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  3. #3
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    Re: integration problem. Please Help

    Quote Originally Posted by girdav View Post
    Did you follow the hint? What did it give you?
    " on expanding the cosh and cosine terms, four separate integrals may be obtained. from symmetry it may be shown that three of these integrals are identically zero leaving " is all i have for the hints.

    after i expend,

    ∫₀2π ((1/2)cosh(a k sinθ)sin(θ+a k cosθ)-(1/2)cosh(a k sinθ)sin(θ-a k cosθ))dθ

    this is what i get and don't know how to continue already....

    if the question is only this ∫₀2π sin(k a cosθ)cosθdθ ... i still know how to do. with cosh( k a sinθ) multiplying inside I really no idea how to solve... any suggestion ??/
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    Re: integration problem. Please Help

    help Please
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