2. ## Re: Evaluate integral

Should work doing integration by parts twice I think.

3. ## Re: Evaluate integral

Originally Posted by Mhmh96
Let's denote :

$I= \int (1-x^2)e^{-2x} \, dx$

Rewrite integral into form :

$I=\int e^{-2x} \,dx - \int e^{-2x} \cdot x^2 \,dx$

For the first integral use substitution :

$-2x=t$

For the second integral use integration by parts :

$u=x^2 ~\text{and}~dv=e^{-2x}dx$