I wrote it by hand and this is just a rough sketch, but I'm just wondering if I got the general shape correct?
The only place I think I might have went wrong is "lim y x-> -2 does not exist".
Any help would be greatly appreciated
I wrote it by hand and this is just a rough sketch, but I'm just wondering if I got the general shape correct?
The only place I think I might have went wrong is "lim y x-> -2 does not exist".
Any help would be greatly appreciated
What does "f(0), f(3) = 0, f''(1) 0" mean?
Since f'(x) < 0 for x < -2 and -2 < x < 0, the function is monotonic on those intervals and therefore has limits from the left and from the right at -2. Since there is no overall limit, the one-sided limits must be different.
Also, you need to make sure the function is concave/convex on the required intervals.
I appreciate the quick response; maybe you're Russian, if so, огромное спасибо)
I believe it means that either a local maximum or local minumum occurs at one of those points?
I believe it means that the point of inflexion is 1.
This is the part I don't get well. The function is monotonic, but not continous, thus the shape must be the same with a small disconnect, no?
I also wasn't sure about this. It says "intervals", as such, does that mean it can simply "begin" being concave or convex or does it have to be completely concave/convex in those intervals? What do you think?
Пожалуйста.
In this case it should say "f '(0) = f '(3) = 0".
In this case it should say "f ''(1) = 0".
Yes, though the phrase "the shape must be the same with a small disconnect" is not precise. See Wikipedia.
You just need to make sure that the second derivative is as required. In your picture, (I understand that it's a sketch), the graph seems to be composed of straight lines whose second derivative is zero.