Find an equation for the line tangent to the curve at the given point x^4+y^3=17 at (-3,-4) Also if you could post the steps it took you to get the answer plz THANKS GUYS!

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Differentiate implicity the function, then plug , so will be the slope of the tangent line. Apply the point-slope formula and you're done. -- I dunno if this is the procedure, I don't remember these things -.-

Originally Posted by flewoveru Find an equation for the line tangent to the curve at the given point x^4+y^3=17 at (-3,-4) Also if you could post the steps it took you to get the answer plz THANKS GUYS! As Krizalid said: So at (-3, -4) the derivative is: Now you know the tangent line at (-3, -4) has a slope of 9/4. Thus So your line is -Dan