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**Vinod** Evaluate $\displaystyle \int \frac{dx}{sin(x)+sin(2x)}$ Wolfram alpha gave me this answer $\displaystyle -\frac23log\left(\frac{3-tan^2\frac x2}{\sqrt tan\frac x2\right)}+c.$ When I solved this problem, I got this answer $\displaystyle \frac16log(1- cos x)+\frac12 log(1+cos x)-\frac23 log (1+2cos x)+c.$ Answer calculated by me is matching with the answer given in the study material.Can any member of this forum tell me which answer is correct? OR both are one and the same?